x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1

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x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1

x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1
x1+5x2-x3-x4=-1
x1-2x2+x3+3x4=3
3x1+8x2-x3+x4=1

x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1
增广矩阵经行变换化成 (字数限制)
1 0 3/7 13/7 13/7
0 1 -2/7 -4/7 -4/7
0 0 0 0 0
通解为:(13/7,-4/7,0,0)'+c1(3,-2,-7,0)'+c2(13,-4,0,-7)',c1,c2 为任意常数

用基础解系表示线性方程组的全部解(1)【2x1-x2+x3-2x4=1 】(2) 【x1-2x2+x3=-5】 (3) 【x1-x2-x3+x4=0】【-x1+x2+2x3+x4=0 】 【x1+5x2-7x3=2】 【x1-x2+x3-3x4=1】【x1-x2-2x3+2x4=-0.5 】 【3x1+x2-5x3=-8】 【x1-x2-2x 用初等行变换来解下列线性方程组(1)2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6(2) x1-2x2+x3+x4=1 x1-2x2+x3-x4=-1 x1-2x2+x3-5x4=5(3) x1-x2+x3-x4=1 x1-x2-x3+x4=0 x1-x2-2x3+2x4=-1/2 线性代数!解非其次线性方程组;【2x1+x2-x3+x4=1;4x1+2x2-2x3+x4=2;2x1+x-x3-x4=1】. 求解非齐次线性方程组x1-2x2+x3+x4=1,x1-2x2+x3-x4=-1,x1-2x2+x3-5x4=5的解 用初等行变换解线性方程组 x1-2x2+x3+x4=1 x1-2x2+x3-x4=-1 x1-2x2+x3-5x4=5 解方程组X1-2x2+3x3-x4=1,3x1-x2+5x3-3x4=2,2x1+x2+2x3-2x4=3 解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2=2 x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1 用消元法解方程组x1+x2-2x2=-3,5x1-2x2+7x3=22.2x1-5x2+4x3=4 是字母x.x1+2x2-x3-2x4=0,2x1-x2-x3+x4=1,3x1+x2-3x3-x4=1 1.用基础解系表示线性方程组的通解X1 +2X2+3X3-X4=13X1+2X+X3-X4=1 2X1+3X2+X3+X4=12X1+2X2+2X3-X4=15X1+5X2+2X3=22.3 1 0A= -4 -1 0 的特征值和特征向量.4 -8 2 1.用基础解系表示线性方程组的通解X1 +2X2+3X3-X4=13X1+2X2+X3-X 非齐次线性方程组求解.x1+x2+2x3+3x4=1 2x1+3x2+5x3+2x4=-3 3x1-x2-x3-2x4=-4 3x1+5x2+2x3-2x4=-10 讨论2X1+X2-X3+X4=1 3X1-2X2+2X3-3X4=2 5X1+X2-X3+2X4=-1 2X1-X2+X3-3X4=4的解的情况 求非齐次线性方程组的通解x1+3x2+5x3-4x4=1x1+3x2+2x3-2x4+x5=-1x1-2x2+x3-x4-x5=3x1+2x2+x3-x4-x5=3 x1-x2+x3=1 x2-x3+x4=2 x3-x4+x5=3 x4-x5+x1=4 x5-x1+x2=5 求x1,x2,x3,x4,x5 写出x的各个答案就行了.x1+x2+x3=5x2+x3+x4=1x3+x4+x5=-5x4+x5+x1=-3x5+x1+x2=2 x1-x2+x3=1x2-x3+x4=21若x1,x2,x3,x4,x5满足方程组 x3-x4+x5=3x4-x5+x1=4x5-x1+x2=5求x2 x3 x4的值2已知 x1+x4+x6+x7=39 x2+x4+x5+x7=49 x3+x5+x6+x7=41 x4+x7=13 x5+x7=14 x6+x7=9 x1+x2+x3+x4+x5+x6+x7=9求x7的值若x1,x2,x3,x4,x5满足方程组 x1-x 求解线性方程组 x1-2x2+3x3-x4-x5=2 x1+x2-x3+x4-2x5=1 2x1-求解线性方程组x1-2x2+3x3-x4-x5=2x1+x2-x3+x4-2x5=12x1-x2+x3-2x5=22x1+2x2-5x3+2x4-x5=5 下列方程组如何解 2x1+x2-2x3+3x4=1 3x1+2x2-x3+2x4=4 3x1+3x2+3x3-3x4=52x1+x2-2x3+3x4=13x1+2x2-x3+2x4=43x1+3x2+3x3-3x4=5如何解这个线性方程组,因为不太懂。