⑴9(x-y)²-25 ⑵(x²-y)²-(2y-2)² ⑶(a²-2b)²-(1-2b

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⑴9(x-y)²-25 ⑵(x²-y)²-(2y-2)² ⑶(a²-2b)²-(1-2b

⑴9(x-y)²-25 ⑵(x²-y)²-(2y-2)² ⑶(a²-2b)²-(1-2b
⑴9(x-y)²-25 ⑵(x²-y)²-(2y-2)² ⑶(a²-2b)²-(1-2b

⑴9(x-y)²-25 ⑵(x²-y)²-(2y-2)² ⑶(a²-2b)²-(1-2b
⑴9(x-y)2-25=(3x-3y+5)(3x-3y-5)
⑵(x2-y)2-(2y-2)2=(x2-y+2y-2)(x2-y-2y+2)=(x2+y-2)(x2-3y+2)
⑶(a2-2b)2-(1-2b)2=(a2-2b+1-2b)(a2-2b-1+2b)=(a2-4b+1)(a2-1)=(a2-4b+1)(a-1)(a+1)

⑴ 9(x-y)²-25
=[3(x-y)+5][3(x-y)-5]
=[3x-3y+5][3x-3y-5]
⑵(x²-y)²-(2y-2)²
=(x^2-y+2y-2)(x^2-y-2y+2)
=(x^2+y-2)(x^2-3y+2)
⑶(a²-2b)²-(1-2b)²
=(a^2-2b+1-2b)(a^2-2b-1+2b)
=(a^2-4b+1)(a+1)(a-1)

⑴9(x-y)²-25 ⑵(x²-y)²-(2y-2)² ⑶(a²-2b)²-(1-2b 求助:几道因式分解题⑴(x+y)^4+(x²-y²)²+(x-y)^4⑵(x^4-4x²+1)(x^4+3x²+1)+10x^4⑶16(6x-1)(2x-1)(3x+1)(x-1)+25⑷a³b-ab³+a²+b²+1⑸(x²-y²)²-8(x²+y&s 分解因式:4b²c²-(b²+c²-a²)² 25(x+y)²-16(x-y)² x²-6x+9 用因式分解法解下列方程(过程要详细)⑴ 2x²+5x=0 ⑵(y-1)(y+3)=-4⑶x(x-2)=4-x² ⑷√3x(x-1)-√2(x-1)=0⑸4(x-1)²=25(x+1)² ⑹√2x(x+1)=x+1⑺x²-9 =1/2(x²-6x+9) 因式分解: 16(x-y)²-9(x+y)² (3x-2y)²(3x-2y)²(9x²+4y²)² 1.(x+y)²-4xy=( )²2.x²-( )+25y²=( )²3.x²-8x²y²+16y四次方=( )²4.7.2²-2.8²= . 已知(x+y)²=25,(x-y)²=9,求xy与x²+y²的值. 已知(x+y)²=25,(x-y)²=9,求xy与x²+y²的值 (x+y)²=25,(x-y)²=9,求x²+y²和xy的值 计算或化简:[(x-y)/(x+3y)]÷[(x²-y²)/(x²+6xy+9y²)]-(2y)/x+y 下列各式不能用平方差公式进行因式分解的是( )A、-a²+b² B、9x²y²-a² C、-y²-x² D、4m²-25n²(只写选项) 数学因式分解题(用平方差公式)!①x²-(y-1)²②-1+(m-1)²③(2x+y)²-(2x-3y)²④25(x-y)²-(x+y)²⑤9(m+n)²-4(2m-n)²⑥(x-y+z)²-(x-y-z)²⑦198²-202² (x+y)²-10(x+y)+25 4m²-9n²-4m+1 约分(初二数学的分式)x²+y²-9-2xy/x²-y²+6x+9 麻烦各位了.数学题(1)12a³b²-9a²+3ab(2)121x²-144y²(3)4(a-b)²-(x-y)²(4)(x-2)²+10(x-2)+25(5)(a²-2ab+b)²-4(6)16x²-4y²(7)m²(x-y)+n²(y-x) 9(x-y)²+12(x²-y²)+4(x+y)² 因式分解 分解公因式 (x+y)²-2(x²-y²)+(x-y)²