作业帮用牛顿切线法求方程f(x)=2x+sinx-4.18=0在区间[0,5]上的近似实根r,迭代初值自选,精确到0.0001.C++
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![用牛顿切线法求方程f(x)=2x+sinx-4.18=0在区间[0,5]上的近似实根r,迭代初值自选,精确到0.0001.C++](/uploads/image/z/5633982-54-2.jpg?t=%E7%94%A8%E7%89%9B%E9%A1%BF%E5%88%87%E7%BA%BF%E6%B3%95%E6%B1%82%E6%96%B9%E7%A8%8Bf%28x%29%3D2x%2Bsinx-4.18%3D0%E5%9C%A8%E5%8C%BA%E9%97%B4%5B0%2C5%5D%E4%B8%8A%E7%9A%84%E8%BF%91%E4%BC%BC%E5%AE%9E%E6%A0%B9r%2C%E8%BF%AD%E4%BB%A3%E5%88%9D%E5%80%BC%E8%87%AA%E9%80%89%2C%E7%B2%BE%E7%A1%AE%E5%88%B00.0001.C%2B%2B)
用牛顿切线法求方程f(x)=2x+sinx-4.18=0在区间[0,5]上的近似实根r,迭代初值自选,精确到0.0001.C++
用牛顿切线法求方程f(x)=2x+sinx-4.18=0在区间[0,5]上的近似实根r,迭代初值自选,精确到0.0001.
C++
用牛顿切线法求方程f(x)=2x+sinx-4.18=0在区间[0,5]上的近似实根r,迭代初值自选,精确到0.0001.C++
#include
#include
void main()
{
void function1();//搜索法
void function2();//二分法
void function4();//牛顿法
int choice;
printf("请选择求解的方法:\n\t1.搜索法\n\t2.二分法\n\t3.牛顿法\n:");
switch(1)
{
case 1:function1();
case 2:function2();
case 4:function4();
}
}
void function1()//搜索法计算非线性方程的解
{
double expression1(double);
double lpoint=1.0,rpoint=2.0,step=0.0001;
while(expression1(lpoint)0.00001)
{
mpoint=(lpoint+rpoint)/2;
if(expression1(lpoint)*expression1(mpoint)0.00001)
{
x=x-expression1(x)/expression2(x);
}
printf("运用牛顿法所求结果:%f\n",x);
}
double expression1(double x)
{
double result;
result=x*x*x-x*x-1;
return result;
}
double expression2(double x)
{
double result;
result=3*x*x-2*x;
return result;
}