若丨a+b+2丨与丨2ab-1丨互为相反数,求式子a+b/3ab-3ab/a+b+1的值.

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若丨a+b+2丨与丨2ab-1丨互为相反数,求式子a+b/3ab-3ab/a+b+1的值.

若丨a+b+2丨与丨2ab-1丨互为相反数,求式子a+b/3ab-3ab/a+b+1的值.
若丨a+b+2丨与丨2ab-1丨互为相反数,求式子a+b/3ab-3ab/a+b+1的值.

若丨a+b+2丨与丨2ab-1丨互为相反数,求式子a+b/3ab-3ab/a+b+1的值.
若丨a+b+2丨与丨2ab-1丨互为相反数,
丨a+b+2丨+丨2ab-1丨=0
a+b=-2
2ab=1
ab=1/2
a+b/3ab-3ab/a+b+1
=-2/(3x1/2)-(3x1/2)/(-2)+1
=-4/3+3/4+1
=-16/12+9/12+1
=5/12
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两个绝对值互为相反数,这两个绝对值必然都要等于0.
a+b+2=0
2ab-1=0
联立解得:a+b=-2,ab=1/2
带入所求:原式=-4/3+3/2=1/6

丨a+b+2丨+丨2ab-1丨=0
a+b=-2 ab=1/2
a+b/3ab-3ab/a+b+1=5/12

∵丨a+b+2丨与丨2ab-1丨互为相反数,
∴丨a+b+2丨+丨2ab-1丨=0
即a+b=-2 ; 2ab=1
∴ab=1/2
∴a+b/3ab-3ab/a+b+1
=-2/(3x1/2)-(3x1/2)/(-2)+1
=-4/3+3/4+1
=-16/12+9/12+1
=5/12