∫dx/(1+e^x)^2=?,x∈[0,ln2]错了错了改为∫e^x(1+e^x)^2dx=?x∈[0,ln2],请回答

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∫dx/(1+e^x)^2=?,x∈[0,ln2]错了错了改为∫e^x(1+e^x)^2dx=?x∈[0,ln2],请回答

∫dx/(1+e^x)^2=?,x∈[0,ln2]错了错了改为∫e^x(1+e^x)^2dx=?x∈[0,ln2],请回答
∫dx/(1+e^x)^2=?,x∈[0,ln2]
错了错了
改为∫e^x(1+e^x)^2dx=?x∈[0,ln2],请回答

∫dx/(1+e^x)^2=?,x∈[0,ln2]错了错了改为∫e^x(1+e^x)^2dx=?x∈[0,ln2],请回答
见图

∫dx/(1+e^x)^2
= ∫(1+e^x)/(1+e^x)^2dx -∫e^x/(1+e^x)^2dx
=∫1/(1+e^x)dx -∫e^x/(1+e^x)^2dx
=∫(1+e^x)/(1+e^x)dx-∫e^x/(1+e^x)dx -∫e^x/(1+e^x)^2dx
=∫1dx-∫e^x/(1+e^x)dx -∫e^x/(1+e^x)^2dx

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∫dx/(1+e^x)^2
= ∫(1+e^x)/(1+e^x)^2dx -∫e^x/(1+e^x)^2dx
=∫1/(1+e^x)dx -∫e^x/(1+e^x)^2dx
=∫(1+e^x)/(1+e^x)dx-∫e^x/(1+e^x)dx -∫e^x/(1+e^x)^2dx
=∫1dx-∫e^x/(1+e^x)dx -∫e^x/(1+e^x)^2dx
=x-ln(1+e^x)+1/(1+e^x)+C
带入积分区间[0,ln2]
=ln2-ln3+1/3
=1/3+ln(2/3)
答案有误吧

收起

∫e^x(1+e^x)^2dx=
u=e^x
∫u(u+1)^2dx
=∫u^3dx+2∫u^2dx+∫udx
=∫u^2du+2∫udu+∫du
=u^3/3+u^2+u
=e^3x/3+e^2x+e^x+c
f(x)=e^3x/3+e^2x+e^x+c
∫e^x(1+e^x)^2dx=f(ln2)-f(0)
=8/3+4+2-1/3-1-1
=19/3