已知{An}成等差数列,Bn=[A(n+1)]^2-An^2,求证数列{Bn}也成等差数列.回答的加悬赏、、

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 00:14:40
已知{An}成等差数列,Bn=[A(n+1)]^2-An^2,求证数列{Bn}也成等差数列.回答的加悬赏、、

已知{An}成等差数列,Bn=[A(n+1)]^2-An^2,求证数列{Bn}也成等差数列.回答的加悬赏、、
已知{An}成等差数列,Bn=[A(n+1)]^2-An^2,求证数列{Bn}也成等差数列.
回答的加悬赏、、

已知{An}成等差数列,Bn=[A(n+1)]^2-An^2,求证数列{Bn}也成等差数列.回答的加悬赏、、
An=A1+(n-1)d
A(n+1)=A1+nd
Bn=(a1+nd)^2-[a1+(n-1)d]^2 =2nd^2+2da1-d^2
B(n-1)=[a1+(n-1)d]^2-[a1+(n-2)d]^2=2nd^2+2da1
Bn-B(n-1)=d^2
可得数列{Bn}是等 差数列

已知数列{an}是等差数列,且bn=an+a(n-1),求证bn也是等差数列 已知数列an是等差数列,且bn=an+a(n+1).求证数列bn是等差数列. 已知数列{An}是等差数列,且Bn=An+A(n+1).求证数列{Bn}是等差数列过程,谢谢 已知{An}成等差数列,Bn=[A(n+1)]^2-An^2,求证数列{Bn}也成等差数列.回答的加悬赏、、 已知{an}是各项为不同正数的等差数列,lga1,lga2,lga4成等差数列.又bn=1[a(2^n)]证明{bn}为等比数列 已知正数列{an}和{bn}满足:对任意n(n属于N*),an,bn,an+1成等差数列且an+1=根号下b已知正数列{an}和{bn}满足:对任意n(n属于N*),an,bn,a(n+1)成等差数列且a(n+1)=根号下bn x b(n+1)判断数列根号下bn为 已知:bn=(a1+2a2+...+nan)/(1+2+...+n),数列an成等差数列的充要条件是bn也是等差数列. 已知正项数列{an},{bn}满足:对任何正整数n,都有an,bn,a(n+1)成等差数列,bn,a(n+1),b(n+1)成等比数列,且a1=10,a2=15求证:数列(根号Bn)是等差数列求数列{an},{bn}通用公式设Sn=1/(a1)+1/(a2)+1/(a3)+.1/(an)如果 已知数列an中,a(n+1)=an/an+1 已知a1=2,bn=1/an,用定义法证明bn是等差数列 【紧急--高一数学】已知数列{an}是首项a1=a,公差为2的等差数列;数列{bn}满足2bn=(n+1)an已知数列{an}是首项a1=a,公差为2的等差数列;数列{bn}满足2bn=(n+1)an(1)若a1,a3,a4成等比数列,求数列{an}的通项 (高二数学)已知数列{an}是首项a1=a,公差为2的等差数列;数列{bn}满足2bn=(n+1)an已知数列{an}是首项a1=a,公差为2的等差数列;数列{bn}满足2bn=(n+1)an(1)若a1,a3,a4成等比数列,求数列{an}的通项公式(2 已知数列an是等差数列 且bn=2^a{n}求证bn为等比数列 {}里为下标 ^为上标 在数列{an}和{bn}中,an>0,bn>0,且an,bn,a(n+1)成等差数列,bn,a(n+1),b(n+1)成等比数列,a1=1,b1=2,求an/bn. 高一数列简单证明题一道An,Bn分别为数列{an},{bn}的前n项和.已知an/bn=A(2n-1)/B(2n-1),求证{an}{bn}为等差数列. 已知数列{an}满足a1=4且a(n+1),an,3成等差数列,其中.已知数列{an}满足a1=4且a(n+1),an,3成等差数列,其中n属于正自然数.1.求证:数列{an-3}是等比数列2.令bn=2n×an-6n,求数列{bn}的通项公式以及前n项 如何证明:已知数列{an}是等差数列,设bn=2an+3a(n+1).求证:数列{bn}也是等差数列. 已知数列{an}是等差数列,且bn=2an +3a(n+1),求证bn也是等差数列 已知数列{an}是等差数列,且bn=2an +3a(n+1),求证bn也是等差数列过程,谢谢!