lim/x→0 /lim 2-2cosx/ sinx^2利用罗必塔法则求极限

求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0 lim(x→0)(cosx-cos^2x)/x^2 lim(x→0)(cosx)^(1/ln(1+x^2)) lim(x→0)(cosx)^[4/(x^2)] lim x→0[ln(cosx)]/x^2 lim(x→0)(cosx)^4/x^2 怎么解 lim/x→0 /lim 2-2cosx/ sinx^2利用罗必塔法则求极限 lim(x→0)[(secx)^2-1] /(1-cosx) lim x→0(1+2cosx)^secx 已知lim(x→0) f(x)/(1-cosx) =2 求lim(x→0) [1+f(x)]^½ 求lim x→0 (tan2x-sinx)/x以及lim x→0 (cosx-cos3x)/x^2 limx→0(cosx)^(1/x^2)求解lim(x→0)((cosx)^(1/x^2)) (1) lim(x->正无穷) x-lnx (2) lim(x->0+) cosx^1/x^2 lim(x→л/2)cosx/(x-л/2) lim(x→0)(1/cosx)=? lim（x趋向于0）（1-cosx)/x^2 lim(x趋向0+)x/[(1-cosx)^(1/2)] lim x->0 cos(2x)-1 / cosx -1 =