f(x)=sin^2(wx)+√3sin(wx)*sin(wx+π/2）w>0的最小正周期为π,求w,f(x)在闭区间0,2π/3上取值范围

f(x)=sin(2wx)＋√3cos(2wx)怎么化成f(x)=sin(2wx＋π/3) 已知函数f x=√3sin(wx+φ/2)*cos(wx+φ/2)+sin^2(wx+φ/2)(w>0,0 已知函数f(x)=√3sin(wx+φ)-cos(wx+φ)(0 已知函数f(x)=√3 sin( wx+φ)-cos(wx+φ) (0 已知函数f(x)=√3 sin( wx+φ)-cos(wx+φ) (0 已知函数f(x)=√3sin(wx+φ)-cos(wx+φ)(0 f(x)=sin^2(wx)+√3sin(wx)*sin(wx+π/2）w>0的最小正周期为π,求w,f(x)在闭区间0,2π/3上取值范围 f(x)=sin^2(wx)+√3sin(wx)*sin(wx+π/2）w>0的最小正周期为π,求w,f(x)在闭区间0,2π/3上取值范围 化简f（x）=2又根号3sin（wx／2）cos（wx／2）-2sin^2wx／2 请问f(x)=根号3sin(wx+φ)-cos(wx+φ)=2Sin(wx+φ-π/6)如何化简? 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2 函数f(x)=√3sin^(wx/2)+sin(wx/2)cos(wx/2) (w>0)的周期为π,求w的值和函数f(x)的单调递增区间 已知函数为f(x)=√3sin(wx+φ)-cos(wx+φ)（w>0,0 f(x)=sin^2 wx+根号3*sinwxcoswx麻烦化简成y=ASin(wx+@)+B的形式. [非常急]已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0 已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0 求教：已知f(x)=根号3*sin(wx+a)-cos(wx+a) (0