y=x*e^y,则dy=

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y=x*e^y,则dy=
y=x*e^y,则dy=

y=x*e^y,则dy=
y=x*e^y,则：y'=e^y+x*e^y*y',所以：y'=e^y/(1-xe^y)=e^y/(1-y)
所以：dy={e^y/(1-y)}dx

y = xe^y
dy = d(xe^y) = dxe^y + xe^ydy
(1 - xe^y)dy = dxe^y
dy = e^ydx / (1 - xe^y) = ydx / [x(1 - y)]

y=e^2x则dy? y=x*e^y,则dy= y=e^2x,dy= y=e^3x,dy=? y=e^-x^2,求dy e^x+e^y=y 确定函数y=f(x) 则dy/dx [e^(x+y)-e^x]dx+[e^(x+y)-e^y]dy=0求通解设函数Y=e^√x,则dy=? 设y=e^(-1/x),则dy=? 设y=3^x+e^3,则dy=? 设y=e(-1/x)次方,则dy= y=e^x-ln3 则 dy/dx等于什么, 设y=[e^x+e^(-x)]^2,求dy 设y=x*e^y,求dy=? x^2+y^2=e^y求dy/dx y=e^x^2 则dy=( )A e^x^2 B e^x^2dx C 2Xe^x^2dy D2e^(2x) dy dy/dx,y=(1+x+x^2)e^x 微分方程通解（1+e^(x/y))dx+e^(x/y)(1-x/y)dy=0