1.已知cosa=3/5,且a属于(3Π/2,2Π),则cos(a-Π/3)= 2.VABC中,sinA=3/5,cosB=5/13,则cosC=?

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1.已知cosa=3/5,且a属于(3Π/2,2Π),则cos(a-Π/3)= 2.VABC中,sinA=3/5,cosB=5/13,则cosC=?

1.已知cosa=3/5,且a属于(3Π/2,2Π),则cos(a-Π/3)= 2.VABC中,sinA=3/5,cosB=5/13,则cosC=?
1.已知cosa=3/5,且a属于(3Π/2,2Π),则cos(a-Π/3)= 2.VABC中,sinA=3/5,cosB=5/13,则cosC=?

1.已知cosa=3/5,且a属于(3Π/2,2Π),则cos(a-Π/3)= 2.VABC中,sinA=3/5,cosB=5/13,则cosC=?
1 cosa=3/5 又a在第四象限,sina= - 4/5 cos(a-pi/3)= 3sqrt(3)/10+2/5
2 cosB = 5/13 则sinB =12/13 sinA =3/5 |cosA|=4/5 当cosA=-4/5时,A+B超过180度,故cosA=4/5 cosC=-cos(A+B)= -56/65

cosa=3/5,a∈(3π/2,2π)
sina=-4/5
cos(a-π/3)=1/2cosa+√3/2sina=(3-4√3)/10
sinA=3/5 cosA=4/5(取负不行),
cosB=5/13 sinB=12/13
cosC=cos[180-(A+B)]
=sinAsinB-cosAcosB=16/65