已知5x^2-4xy+y^2-2x+1=0,求(x-y)^2007

已知5x^2-4xy+y^2-2x+1=0,求(x-y)^2007
已知5x^2-4xy+y^2-2x+1=0,求(x-y)^2007

已知5x^2-4xy+y^2-2x+1=0,求(x-y)^2007
5x^2-4xy+y^2-2x+1
=(x^2-2x+1)+(4x^2-4xy+y^2)
=(x-1)^2+(2x-y)^2=0
所以,x-1=0,2x-y=0
x-y=(2x-y)-x=-1
(x-y)^2007=-1