已知x²y+2xy²=2,求(x²y-2xy²)+(x²y+6xy²)的值

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已知x²y+2xy²=2,求(x²y-2xy²)+(x²y+6xy²)的值

已知x²y+2xy²=2,求(x²y-2xy²)+(x²y+6xy²)的值
已知x²y+2xy²=2,求(x²y-2xy²)+(x²y+6xy²)的值

已知x²y+2xy²=2,求(x²y-2xy²)+(x²y+6xy²)的值
x²y=2-2xy²
(2-2xy²-2xy²)+(2-2xy²+6xy²)
=(2-4xy²)+(2+4xy²)
=4
ok啦,给分啊!