1/1*3+1/3*5+1/5*7+.1/99*101等于多少

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1/1*3+1/3*5+1/5*7+.1/99*101等于多少

1/1*3+1/3*5+1/5*7+.1/99*101等于多少
1/1*3+1/3*5+1/5*7+.1/99*101等于多少

1/1*3+1/3*5+1/5*7+.1/99*101等于多少
数学归纳法很简单的
通项是1/(2k+1)*(2k-1)的 就是利用分子式化简成两个分母相减 提出个恒定差就行 里面就是两个公比数列求和
这么算就是 99/101

1/1*3+1/3*5+1/5*7+.....1/99*101
=2(1/2-1/3+1/3-1/5+-----+1/99-1/101)
=2(1/2-1/101)
=2*99/202
=99/101

用裂项相消
1/1*3+1/3*5+1/5*7+.....1/99*101
=2(1/2-1/3+1/3-1/5+-----+1/99-1/101)
=2(1/2-1/101)
=2*99/202
=99/101

1-3+5-7+... (1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简算(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简便计算 1/1*3+1/1*3*5+1/1*3*5*7+1/1*3*5*7*9-73/945 1/3+1/5+1/7+.+1/2n+1 (1/3+1/5+1/7)*(1/5+1/7+1/9)-(1/3+1/5+1/7+1/9)*(1/5+1/7)=? 1 1 1 1 1 3 5 7 1 5 13 25 1 7 25 why 1/1×3+1/3×5+1/5×7+1/7×9.+1/2011×2013 简算:1/1*3+1/3*5+1/5*7+1/7*9+1/9*11 1/1*3+1/3*5+1/5*7+1/7*9+...1/17*19= 计算1/(1×3)+1/(3×5)+1/(5×7)+1/(7×9)+.+1/(19×21) 1/1×3+1/3×5+1/5×7+1/7×9+.+1/2013×2015 1/1*3+1/3*5+1/5*7+1/7*9+.+1/101*103 帮帮忙1/1*3+1/3*5+1/5*7+1/7*9+...1/99*101 1/1*3+1/3*5+1/5*7+1/7*9+1/49*51= 计算：1/1×3+1/3×5+1/5×7+1/7×9``````+1/2001×2003 (1*3)/1+(3*5)/1+(5*7)/1+(7*9)/1+(9*11)/1 1/1*3+1/3*5+1/5*7+1/7*9+1/9*11 (1*3)/1+(3*5)/1+(5*7)/1+(7*9)/1+(9*11)/1