f(x)=x(x-1)(x-2).(x-10),则f'(9)=

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f(x)=x(x-1)(x-2).(x-10),则f'(9)=

f(x)=x(x-1)(x-2).(x-10),则f'(9)=
f(x)=x(x-1)(x-2).(x-10),则f'(9)=

f(x)=x(x-1)(x-2).(x-10),则f'(9)=
依题意得:
f'(x)=(x-1)(x-2)…(x-10)+ x(x-2)…(x-10) + … + x(x-1)…(x-9)
∴f'(9)=8*7*6*…*0*(-1)+9*8*…0*(-1)+ … +9*8*…*0*(-1)
=9*8*7*6*5*4*3*2*1*(-1) (注:其它项都含0)
=按计算器去吧~